If the value of $p^{2} + q^{2} = 21$ and $p q = 30$ , then find the value of $(p + q)^{2}$
81

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Solution

The correct option is A 81
Given,
$p^{2} + q^{2} = 21$ , $p q = 30$

We know that,
$(p + q)^{2} = p^{2} + q^{2} + 2 p q$
$(p + q)^{2} = 21 + 2 \times 30$
$(p + q)^{2} = 21 + 60$
$(p + q)^{2} = 81$

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