If the value of $p^{2} + q^{2} = 21$ and $p q = 30$ , then find the value of $(p + q)^{2}$

Open in App

Solution

Given,
$p^{2} + q^{2} = 21$ , $p q = 30$

We know that,
$(p + q)^{2} = p^{2} + q^{2} + 2 p q$
$(p + q)^{2} = 21 + 2 \times 30$
$(p + q)^{2} = 21 + 60$
$(p + q)^{2} = 81$

Suggest Corrections

Similar questions

p^{2} + q^{2} = 21

p q = 30

(p + q)^{2}

p^{2} x^{2} + (p^{2} - q^{2}) x - q^{2} = 0, p \neq 0

p q x^{2} - (p^{2} + q^{2}) x + p q = 0,

x

Let p and q are distinct naturals such that 2005+p=q² and 2005+q=p².Find the value of 2014+pq

p c o t θ = \sqrt{q^{2} - p^{2}}

s i n θ

Explore more