If the value of $x = - 2$ , $y = 3$ , $z = 1$ , then find the value of the following :
$4 x y z - x^{3}$

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Solution

Given that :
$x = - 2$ , $y = 3$ , $z = 1$
And we have to find the value of the expression :
$4 x y z - x^{3}$
Finding the value of the expression at the given values of variables :
So
$4 x y z - x^{3} = 4 (- 2) (3) (1) - {(- 2)}^{3} = 4 (- 6) - (- 8) = - 24 + 8 = - 16$
Therefore value of the given expression at $x = - 2$ , $y = 3$ , $z = 1$ is :
$4 x y z - x^{3} = - 16$

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