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Elimination Method of Finding Solution of a Pair of Linear Equations

If the value ...

Question

If the value of y is 3 then find value of x if $\frac{1}{x} + \frac{1}{y} = \frac{5}{6}$

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Solution

$\frac{1}{x} + \frac{1}{y} = \frac{5}{6} 6 y + 6 x = 5 x y 6 (3) + 6 x = 5 (3) x 6 x + 18 = 15 x 9 x = 18 x = 2$

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{sin}^{- 1} x + {sin}^{- 1} y = \frac{2 π}{3}

, then find the value of

{cos}^{- 1} x + {cos}^{- 1} y

- 1 \leq x, y \leq 1

{sin}^{- 1} x + {sin}^{- 1} y = \frac{π}{2},

find the value of

{cos}^{- 1} x + {cos}^{- 1} y .

{sin}^{- 1} x + {sin}^{- 1} y = \frac{2 π}{3}, {cos}^{- 1} y = \frac{π}{3}

, then the number of values of

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, then the least value of

\frac{1}{x} + \frac{1}{y} + \frac{1}{z}

\sin^{- 1} x + \sin^{- 1} y = \frac{π}{3}

\cos^{- 1} x - \cos^{- 1} y = \frac{π}{6}

, find the values of x and y.

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Elimination Method of Finding Solution of a Pair of Linear Equations

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