If the vector −3^i+4^j−2^k,^i+2^k,^i−p^j are coplanar, then the value of p is
A
−2
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B
1
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C
−1
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D
2
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Solution
The correct option is B2 The given vectors are −3^i+4^j−2^k,^i+2^k and ^i−p^j. Let →a=−3^i+4^j−2^k →b=^i+2^k and →c=^i−p^j. If the vector →a,→b and →c are coplanar, then [→a→b→c]=0 ⇒∣∣
∣∣−34−21021−p0∣∣
∣∣=0 ⇒−3(0+2p)+4(2−0)−2(−p−0)=0 ⇒−6p+8+2p=0 ⇒−4p+8=0 ⇒4p=8 ⇒p=2 Hence, the correct answer from the given alternatives is option D.