If the vector →b is collinear with →a=(2√2,−1,4) and |→b|=10, then
A
→a=±→b
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B
→a=±2→b
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C
→b=±→a
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D
→b=±2→a
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Solution
The correct option is D→b=±2→a →a=(2√2,−1,4) and |→b|=10
Given vector →b is collinear with →a. →b=k→a ⇒|→b|=10 ⇒10=√(2√2k)2+(−1k)2+(4k)2 ⇒25k2=100 ∴k=±2 ⇒→b=±2→a