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Question

If the vectors ^i^j,^j+^k and ^a form a triangle, then ^a may be

A
^i^k
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B
^i2^j^k
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C
2^i+^j+^k
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D
^i+^k
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Solution

The correct option is A ^i^k
AB=^i^j,CB=^j^k,CA=^a
AB+BC+CA=ba+cb+ac=0
^i^j+^j+^k+^a=0^a=^i^k

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