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Question

If the vectors a=^i+^j+^k,b=^i^j+2^k,c=x^i+(x2)^j^k are coplanar, then x=

A
1
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B
2
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C
0
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D
2
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Solution

The correct option is C 2
Given equations are a=^i+^j+^k,b=^i^j+2^k,c=x^i+(x2)^jk
These all are coplanar.
Therefore, ∣ ∣111112xx21∣ ∣=0
[(1)2x+4]1[12x]+1(x2+x)=0
4+2x=0
x=2

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