Question

If the velocity hydrogen molecule is $5\times {10}^{4}cm{sec}^{-1}$, then its de Broglie wavelength is?

• A. $2\mathring{A}$
• B. $4\mathring{A}$
• C. $8\mathring{A}$
• D. $100\mathring{A}$

Answer 1

Answer: (C)

$8\mathring{A}$

According to de Broglie wavelength form

$\lambda =\frac{h}{mv}$

$\Rightarrow \lambda =\frac{b.b\times {10}^{-34}}{1.67\times {10}^{27}\times 5\times {10}^2}$

$=8A^{\circ }$