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Question

If the velocity of hydrogen molecule is 5 × 104 cmsec1,then its de-Broglie wavelength is


A

2 Å

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B

4 Å

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C

8 Å

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D

100 Å

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Solution

The correct option is

D

4 Å



According to de-Broglie

λ = hmv = 6.62 × 1020 erg.sec26.023 × 1023 × 5 × 104 cm/sec

= 6.62 × 1027 × 6.023 × 10232 × 5 × 104cm

= 4 × 108 cm = 4Å

As per rules of division and multiplication 2 has to be multiplied and the Avogadro number moves up.


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