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Question

If the vertices of a triangle A,B,C are A(0,0),B(2,1),C(9,2) then cosB=

A
16517
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B
21290
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C
1657
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D
11290
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Solution

The correct option is D 11290
REF.Image.
using law of cosines; we get
(AC)2=(BC)2+(AB)22(BC)(AB)cosB
85=58+52585cosB
8563=2585cosB
222585=cosB
11585=cosB
cosB=11290

1383305_1211627_ans_9240cda10a2c4019b54be9ccab80b97a.PNG

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