If the volume of a cuboid is $3 x^{2} - 27$ , then its possible dimensions are

$3, x^{2}, - 27 x$

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$3, x - 3, x + 3$

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$3, x^{2}, 27 x$

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3, 3, 3

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Solution

The correct option is B
$3, x - 3, x + 3$

$V o l u m e = 3 x^{2} - 27 = 3 (x^{2} - 9) = 3 (x + 3) (x - 3) ∴ Dimensions are = 3, x - 3, x + 3$

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