Question

If the width of each of ten classes in a frequency distribution is 2.5 and the lower class boundary is 5.1, then the upper class boundary of the highest class is

• A. 30.1
• B. 30
• C. 31.1
• D. 27.6

Answer 1

The correct option is A 30.1

Let x and y be the upper and lower class limit of frequency distribution

Given width of class =$10$ and $y=5.1$

$\Rightarrow x-y=2.5$

$\Rightarrow x=7.6$

$\Rightarrow x=7.6$ is the upper class limit of lowest class

$\Rightarrow$upper class limit of highest class =(number of continuous classes ×class width +lower class limit of lowest class)

$=(10\times 2.5)+5.1=30.1$