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Atomic Number and Mass Number

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Question

If there are three moles of $H_{2} O$ for every one mole of $L i C l O_{4}$ , what is the hydrate formula?

L i C l O_{4} \cdot 3 H_{2} O

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3 L i C l O_{4} \cdot 3 H_{2} O

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3 L i C l O_{4} \cdot H_{2} O

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L i C l O_{4} \cdot (H_{2} O)_{3}

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3 (L i C l O_{4}) \cdot 3 (H_{2} O)_{3}

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Solution

The correct option is B $L i C l O_{4} \cdot 3 H_{2} O$
If there are three moles of $H_{2} O$ for every one mole of $L i C l O_{4}$ . The hydrate formula would be $L i C l O_{4} \cdot 3 H_{2} O$

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Similar questions

L i C l O_{4}

N a C l O_{4}

L i^{+}

L i C l O_{4}, N a C l O_{4}, K C l O_{4}, a n d R b C l O_{4}

x

K I

{K I O}_{3}

I_{2}

K O H

\frac{1}{x}

6 K O H + 4 I_{2} ⟶ 5 K I + K I O_{3} + 3 H_{2} O

K I + K I O_{3} H^{+} - - \to I_{2} + H_{2} O

{I O}_{4}^{-}

I O_{4}^{-} + 2 I^{-} + H_{2} O ⟶ I O_{3}^{-} + I_{2} + 2 O H^{-}

I O_{3}^{-} + 5 I^{-} + 6 H^{+} ⟶ 3 I_{2} + 3 H_{2} O

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