You visited us 1 times! Enjoying our articles? Unlock Full Access!

Physical Properties (Group 1)

The correct o...

Question

The correct order for increasing solubility for $L i C l O_{4}, N a C l O_{4}, K C l O_{4}, a n d R b C l O_{4}$ is :

R b C l O_{4} < K C l O_{4} < N a C l O_{4} < L i C l O_{4}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

R b C l O_{4} < K C l O_{4} < L i C l O_{4} < N a C l O_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

R b C l O_{4} < N a C l O_{4} < K C l O_{4} < L i C l O_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

K C l O_{4} < R b C l O_{4} < N a C l O_{4} < L i C l O_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $R b C l O_{4} < K C l O_{4} < N a C l O_{4} < L i C l O_{4}$
solubility: As we move from top to bottom in a group the Solubility of chlorites in water will be decreased due to decrease in bond strength and increase in bond length.
So the correct order of solubility of chlorites is $R b C l O_{4} < K C l O_{4} < N a C l O_{4} < L i C l O_{4}$
Hence option A is correct.

Suggest Corrections

Similar questions

L i C l O_{4}

N a C l O_{4}

L i^{+}

H_{2} O

L i C l O_{4}

N a C l O_{3}

N a C l O_{4}

N a C l O_{3} + H_{2} O \to N a C l O_{4} + H_{2}

N a C l O_{4}

N a C l O_{3}

N a C l O_{3}

N a C l O_{4}

N a C l O_{3} + H_{2} O \to N a C l O_{4} + H_{2}

N a C l O_{4}

N a C l O_{3}

K C l O_{4}

Join BYJU'S Learning Program