Question

If there are two possible positive integer values for $x$ satisfying $y=x(1+x)$. What is a possible value for $y$?

• A. $-30$
• B. $-1$
• C. $0$
• D. $15$
• E. $20$

Answer 1

Answer: (E)

$20$

X	1	2	3	4
Y	2	6	12	20

It is given that x is positive. Therefore $y>0$. Now, we can observe that $y$ is the product of two consecutive integers. Hence the smallest possible value of $x$ is $1$.
Hence, a possible answer is $20$.