Question

If $\theta ={45}^o$, then find $\tan \theta$.

Answer 1

Given $\theta ={45}^{\circ }$

$\therefore tan\theta =tan{45}^{\circ }=\frac{sin{45}^{\circ }}{cos{45}^{\circ }}=\frac{\frac{1}{\sqrt{2}}}{\frac{1}{\sqrt{2}}}=1$

$\therefore tan{45}^{\circ }=1$