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Question

If θ is the angle between the lines AB and CD, then the projection of line segment AB on line CD, is


  1. ABsinθ

  2. ABcosθ

  3. ABtanθ

  4. CDcosθ

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Solution

The correct option is B

ABcosθ


Explanation for the correct answer:

Consider the figure

Let EB be the perpendicular from the point B to the line CD.

A right-angled triangle AEB is thus formed.

As the angle between lines AB and CD is θ.

So, BAE=θ

The projection of the segment AB on line CD is segment AE.

In AEB,

AEAB=cosθ

AE=ABcosθ
Hence, the projection of segment AB on line CD is ABcosθ.

Thus, option(B) is the correct answer.


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