If three coins are tossed, find the probability of getting at least one tail.

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Solution

The complementary event is getting all heads, that is, HHH. Since there are a total of 8 outcomes, the probability of the complementary event is $\frac{1}{8}$ .
Hence, the required probability is 1 – $\frac{1}{8}$ = $\frac{7}{8}$ .

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