Question

If three coins are tossed simultaneously, then find the probability of getting at least two heads.

Answer 1

Find the probability of getting at least two heads

Possible of outcomes when three coins are tossed : $\left\{\left(HHH\right),\left(HHT\right),\left(HTH\right),\left(THH\right),\left(TTT\right),\left(TTH\right),\left(THT\right),\left(HTT\right)\right\}$
Total number of outcomes $=8$
Number of outcomes that has at least two heads $=4$
Probability of an event $=\frac{favorableoutcomes}{Totaloutcomes}$

Probability of getting at least two heads $=\frac{4}{8}$
$=\frac{1}{2}$

Hence, the required probability is $\frac{1}{2}$