Question

if three coins are tossed simutaneously than find the probability of getting atleast two heads

Answer 1

A coin has two sides head (H) and tail(T).

If we toss three coins then the possible outcomes are as follows:


(H,H,H) (H,H,T),(H,T,H),(T,H,H),(H,T,T),(T,H,T),(T,T,H) & (T,T,T)


SOLUTION:


Number of possible outcomes=8

{(H,H,H) (H,H,T),(H,T,H),(T,H,H),(H,T,T),(T,H,T),(T,T,H) & (T,T,T)}


Number of favourable outcomes (at least 2heads)=4


Probability (at least 2headd)= Number of favourable outcomes/total number of outcomes


Probability(P)(at least 2heads)= 4/8=½


P(at least 2 heads)= ½


Hence, the probability of getting at least 2 heads= ½.


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