If three coins tossed simultaneously, then the probability of getting at least two heads is :

\frac{1}{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{3}{8}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{2}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $\frac{1}{2}$
Sample space (S) = $(H H H, H H T, H T H, H T T, T H H, T H T, T T H, T T T)$

$n (S) = 8$

Favorable outcomes = $(H H H, H H T, T H H, H T H)$

$n (E) = 4$

Required probability = $\frac{4}{8} = \frac{1}{2}$

Suggest Corrections

Similar questions

100

- 14

- 38

- 36

- 12

2

3

Find the probability of getting at least two heads if three coins are tossed simultaneously.

1.

2.

3.

Join BYJU'S Learning Program