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Question

If three numbers (x,y,z)=(23,76,89), then the H.C.F. of x,y,z is

A
13
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B
19
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C
23
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D
118
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Solution

The correct option is D 118
H.C.F. of 23,76,89 is H.C.F.(2,7,8)L.C.M.(3,6,9)=118

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