If three numbers x - y - z -2-3- 7-6- 8-9- then the L-C-M- of x - y - z is56-96B- 3-28C- 4-28D- 28-3

The correct option is B 563L.C.M. of nbsp;23,76,89 is L.C.M.(2,7,8)H.C.F.(3,6,9)=563 ...

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Manipulation of a linear equation

If three numb...

Question

If three numbers $(x, y, z) = (\frac{2}{3}, \frac{7}{6}, \frac{8}{9}),$ then the L.C.M. of $x, y, z$ is

\frac{56}{9}

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\frac{56}{3}

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\frac{28}{9}

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\frac{28}{3}

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Solution

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Similar questions

(x, y, z) = (\frac{2}{3}, \frac{7}{6}, \frac{8}{9}),

x, y, z

2 x - 4 y + 9 z = 28

7 x + 3 y - 5 z = 3

9 x + 10 y - 11 z = 4

(x, y, z) = (\frac{2}{3}, \frac{7}{6}, \frac{8}{9})

108 (L.C.M. \times H.C.F.) = p \times q

p, q

(p, q)

Factors of $27 x^{3} + y^{3} + z^{3} - 9 x y z$ are:

{(x + y)}^{3} - z^{2} = 4

{(y + z)}^{2} - x^{2} = 9

{(z + x)}^{2} - y^{2} = 36

x + y + z

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