If three parallel lines l, m, n which are cut by the transversals ¯¯¯¯¯¯¯¯AB and ¯¯¯¯¯¯¯¯¯CD at P, Q, R and E, F, G respectively, then which of the following is not true?
A
PQQR=EFFG
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B
PQPR=EFEG
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C
QRPR=FGEG
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D
PQPR=PERG
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Solution
The correct option is DPQPR=PERG
l || m || n are cut by the transversals ¯¯¯¯¯¯¯¯AB and ¯¯¯¯¯¯¯¯¯CDat P, Q, R and E, F, G respectively.
join PG which intersects m at O.
In ΔPRG,QO||RG PQQR=POOG.........(i)
In ΔPGE,OF||PE POOG=EFFG.........(ii)
From (i) and (ii) PQQR=EFFG.........(iii) ⇒PQQR+1=EFFG+1 ⇒PQ+QRQR=EF+FGFG ⇒PRQR=EGFG ⇒QRPR=FGEG
Taking reciprocal of (iii), we get QRPQ=FGEF ⇒QRPQ+1=FGEF+1 ⇒PRPQ=EGEF ⇒PQPR=EFEG
Clearly, PQPR≠PERG
Hence, the correct answer is option (4).