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Question

If three successive coefficients in the expansion of (1+x)n are 220,495 and 792, then find n.

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Solution

Let the three successive coefficients in (1+x)n are nCr1,nCr,nCr+1
nCrnCr1=nr+1r=495220
nr+1r=9413r4n=4(1)
nCr+1nCr=nrr+1=792495
nrr+1=855n13r=8(2)
(1)+(2)n=12

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