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Question

If TP and TQ are two tangents to a circle with centre O so that ∠POQ = 110°, then, ∠PTQ is equal to

(a) 60°

(b) 70°

(c) 80°

(d) 90°

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Solution

Let us first put the given data in the form of a diagram.

It is given that,

We have to find

We know that the radius of the circle will always be perpendicular to the tangent at the point of contact. Therefore,

Also, we know that sum of all angles of a quadrilateral will always be equal to 360°. Therefore in quadrilateral TQOP, we have,

Therefore, the correct answer to this question is choice (b).


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