Question

If $△ABC\sim △PQR$ and $\angle A={30}^o.\angle R={65}^o$ then find $\angle Q$.

Answer 1

$\Delta$ABC $\sim \Delta$PQR$\Rightarrow \angle A=\angle P={30}^o$

In $\Delta PQR$, sum of angles $={180}^o$

$\Rightarrow \angle P+\angle Q+\angle R={180}^o$

$30+65+\angle Q={180}^o$

$\Rightarrow \angle Q={85}^o$.