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Hydrides of Group 16

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Question

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(i) A white precipitate (B) is formed, when a mineral (A) is boiled with ${N a}_{2} {C O}_{3}$ solution.
(ii) The precipitate is filtered an the filtrate contains two compounds (C) and (D). The compound (C) is removed by crystallisation and when ${C O}_{2}$ is passed through the mother liquor left, (D) changes to (C).
(iii) The compound (C) on strong heating gives two compound (D) and (E).
(iv) E on heating with $C o O$ forms blue colour bead (F).
(A) to (F) are identified as (A) : $C a_{2} B_{6} O_{11}$ , $C a C O_{3}$ , $N a_{2} B_{4} O_{7}$ , $N a B O_{2}$ , $B_{2} O_{3}$ and $C o (B O_{2})_{2}$

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Solution

The compound (A) is $C a_{2} B_{6} O_{11}$
The compound (B) is $C a C O_{3}$
The compound (C) is $N a_{2} B_{4} O_{7}$
The compound (D) is $N a B O_{2}$
The compound (E) is $B_{2} O_{3}$
The compound (F)is $C o (B O_{2})_{2}$
(i) A white precipitate (B) is formed, when a mineral (A) is boiled with ${N a}_{2} {C O}_{3}$ solution.
$C a_{2} B_{6} O_{11} (A) + 2 n a_{2} C O_{3} ⟶ 2 C a C O_{3} (B) + N a_{2} B_{4} O_{7} (C) + 2 N a B O_{2} (D)$
(ii) The precipitate is filtered an the filtrate contains two compounds (C) and (D). The compound (C) is removed by crystallisation and when ${C O}_{2}$ is passed through the mother liquor left, (D) changes to (C).
$4 N a B O_{2} (D) + C O_{2} ⟶ N a_{2} B_{4} O_{7} (C) + N a_{2} C O_{3}$
(iii) The compound (C) on strong heating gives two compound (D) and (E).
$N a_{2} B_{4} O_{7} △ \to 2 N a B O_{2} (D) + B_{2} O_{3} (E)$
(iv) E on heating with $C o O$ forms blue colour bead (F).
$C o O + B_{2} O_{3} ⟶ C o (B O_{2})_{2} (F)$

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