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Major elimination product if the given compounds is heated with strong base is ${C H}_{3} - C H = C H - C O O H (t r a n s)$ .

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Solution

When 2-bromopentanoic acid is heated with strong base, it undergoes dehydrobromination to form (E)-pent-2-enoic acid. The trans alkene is more stable than cis alkene. Moreover in the given compound, the carbon carbon double bond is in conjugation with carboxylic group.

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