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Oxides and Oxoanions

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$S O_{2}$ turns acidified $K_{2} C r_{2} O_{7}$ solution green. Oxidation number of the green coloured ion is 3

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Solution

$S O_{2}$ turns acidified $K_{2} C r_{2} O_{7}$ solution green. Oxidation number of the green coloured ion is 3.
reduces potassium dichromate to green coloured chromium sulphate $(C r_{2} (S O_{4})_{3})$
$C r_{2} O_{7}^{2 -} + 2 H^{+} + 3 S O_{2} \to 2 C r^{3 +} + 3 S O_{4}^{2 -} + 5 H_{2} O$

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