Question

If two algebraic equations are given as $x+10=4\&10-y=4$, then the value of $x+y$ is

• A. $0$
• B. $12$
• C. $-12$

Answer 1

The correct option is A $0$

Given first algebraic equation : $x+10=4$
Subtract $10$ from both the sides
$x+10-10=4-10$
$\Rightarrow x=-6$

Given second algebraic equation: $10-y=4$
Add $y$ on both the sides
$10-y+y=4+y$
$\Rightarrow 10=4+y$
Subtract $4$ from both the sides
$\Rightarrow 10-4=4+y-4$
$\Rightarrow 6=y\text{or}y=6$

$\therefore x+y=(-6)+6=0$