If two balls each of mass $0.06 k g$ moving in opposite directions with same speed $4 m / s$ collide and rebound with the same speed, then the impulse imparted to each
ball due to other is

0.48 k g - m / s

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0.24 k g - m / s

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0.81 k g - m / s

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Z e r o

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Solution

The correct option is A $0.48 k g - m / s$
We know that,

The impulse is

Impulse = change in momentum

$= m v$

$= m (v_{2} - v_{1})$

$= 0.06 \times (4 - (- 4))$

$= 0.06 \times 8$

$= 0.48 k g m / s$

Hence, the impulse is $0.48 k g m / s$

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