If two bodies are projected at an angle 'x' and '90-x' respectively with same velocity then

Their ranges are same

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Their heights are same

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Their times of flight are same

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All of these

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Solution

The correct option is A Their ranges are same
For complimentary angles, $θ, 90^{\circ} - θ$ range of projectile is same.

$R_{1} = \frac{u^{2} 2 s i n θ c o s θ}{g}, R_{2} = \frac{u^{2} s i n (90^{\circ} - θ) c o s (90^{\circ} - θ)}{g}$

$R_{2} = \frac{u^{2} 2 c o s θ s i n θ}{g}$

$∴ R_{1} = R_{2}$

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If two bodies are projected at an angle 'x' and '90-x' respectively with same velocity then

The correct option is A Their ranges are sameFor complimentary angles, θ,90∘−θ range of projectile is same. R1=u2 2sinθ cos θg,R2=u2 sin(90∘−θ)cos(90∘−θ)g R2=u2 2cosθsinθg ∴R1=R2