If two charges of $1$ coulomb each are placed $1 k m$ apart in vacuum, the force between them will be:

9 \times 10^{3} N

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9 \times 10^{- 3} N

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1.1 \times 10^{- 4} N

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10^{- 6} N

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Solution

The correct option is A $9 \times 10^{3} N$
$Q = 1 C$ $r = 1000 m$
$F = \frac{K Q Q}{r^{2}} = \frac{9 \times 10^{9}}{((10)^{3})^{2}} = 9 \times 10^{3} N$

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If two charges of 1 coulomb each are placed 1 km apart in vacuum, the force between them will be:

The correct option is A 9×103NQ=1C r=1000mF=KQQr2=9×109((10)3)2=9×103N

If two charges of $1$ coulomb each are placed $1 k m$ apart in vacuum, the force between them will be:

The correct option is A $9 \times 10^{3} N$
$Q = 1 C$ $r = 1000 m$
$F = \frac{K Q Q}{r^{2}} = \frac{9 \times 10^{9}}{((10)^{3})^{2}} = 9 \times 10^{3} N$