Question

If two dice are thrown simultaneously then probability that $1$ comes on first dice is

• A. $\frac{1}{36}$
• B. $\frac{5}{36}$
• C. $\frac{1}{6}$
• D. None of these

Answer 1

The correct option is C

$\frac{1}{6}$

Explanation for the correct option:

Finding the probability:

Total number of outcomes when die is thrown twice $=6\times 6$

$=36$

Number of a possible event that $1$ comes on the first dice $=\left\{\left(1,1\right)\left(1,2\right)\left(1,3\right)\left(1,4\right)\left(1,5\right)\left(1,6\right)\right\}$

Total number of favorable outcomes $=6$

$\begin{array}{rcl}\mathrm{Probability}\mathrm{that}1\mathrm{comes}\mathrm{on}\mathrm{first}\mathrm{dice}& =& \frac{\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{favourable}\mathrm{outcomes}}{\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{outcomes}}\\ & =& \frac{6}{36}\\ & =& \frac{1}{6}\end{array}$

Hence, the correct option is C.