If two of the zeros of the cubic polynomial ax³ + bx² + cx + d are each equal to zero, then the third zero is

(a) $\frac{- d}{a}$
(b) $\frac{c}{a}$
(c) $\frac{- b}{a}$
(d) $\frac{b}{a}$

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Solution

Let and be the zeros of the polynomial

Therefore

The value of

Hence, the correct choice is

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Similar questions

a x^{3} + b x^{2} + c x + d

If two of the zeros of the cubic polynomial $a x^{3} + b x^{2} + c x + d$ are 0 then the third zero is

(a) $\frac{- b}{a}$ (b) $\frac{b}{a}$ (c) $\frac{c}{a}$ (d) $\frac{- d}{a}$

\frac{- c}{a}

\frac{c}{a}

\frac{- b}{a}

\frac{- b}{a}

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\frac{c}{a}

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If one of the zeros of the cubic polynomial $a x^{3} + b x^{2} + c x + d$ is 0 then the product of the other two zeros is

(a) $\frac{- c}{a}$ (b) $\frac{c}{a}$ (c) 0 (d) $\frac{- b}{a}$

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