CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
256
You visited us 256 times! Enjoying our articles? Unlock Full Access!
Question


If u=ax2+2hxy+by2,

then x2uxy+y2uy2=?

A
2(hx+by)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
2(hxby)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2(bx+hy)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2(bxhy)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 2(hx+by)

ux=2ax+2hy
d2uxy=2h
uy=2hx+2by
d2uy2=2b

xd2uxy+yd2uy2=2hx+2by


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Higher Order Derivatives
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon