If $U = {1, 2, 3, 4, 5, 6, 7, 8, 9}, A = {1, 2, 3, 4}, B = {2, 4, 6, 8}$ and $C = {1, 4, 5, 6}$ , find :
$(B - C)^{'}$

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Solution

$U = {1, 2, 3, 4, 5, 6, 7, 8, 9}, A = {1, 2, 3, 4}, B = {2, 4, 6, 8}$ and $C = {1, 4, 5, 6}$

$(B - C) = {2, 4, 6, 8} - {1, 4, 5, 6} = {2, 8}$

$(B - C)^{'} = U - (B - C) = {1, 2, 3, 4, 5, 6, 7, 8, 9} - {2, 8}$ $= {1, 3, 4, 5, 6, 7, 9}$

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Similar questions

Let U = {1,2,3,4,5,6,7,8,9}, A = {1,2,3,4}, B = {2,4,6,8} and C = {3,4,5,6}. Find :

(i) $A^{'}$ (ii) $B^{'}$ (iii) $(A \cap C)^{'}$

(iv) $(A \cup B)^{'}$ (v) ${(A^{'})}^{'}$ (vi) $(B - C)^{'}$

A'

B'

(A \cap C)'

(A \cup B)'

(A')'

(B - C)'

U = {1, 2, 3, 4, 5, 6, 7, 8, 9} A = {1, 2, 3, 4}

B = {2, 4, 6, 8}

(A \cup B)^{1} = A^{1} \cap B^{1}

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