If U RMS of a gas is 30 R 1-2 ms -1 at 27 -C then the molar mass of gas is -

The correct option is D 1 kg/mol U_rms #160; = √(3RTM) Given, U_rms = 30R^1/2 30R^1/2 = √(3R(300)M) M = 1kg/molHence, Option ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Relating Translational KE and T

If U RMS of...

Question

If $U_{R M S}$ of a gas is 30 $R^{1 / 2}$ ${m s}^{- 1}$ at $27^{\circ} C$ then the molar mass of gas is :

0.02

k g / m o l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.001

k g / m o l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.003

k g / m o l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1

k g / m o l

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $1$ $k g / m o l$
$U_{r m s} = \sqrt{\frac{3 R T}{M}}$

Given, $U_{r m s} = 30 R^{1 / 2}$

$⟹ 30 R^{1 / 2} = \sqrt{\frac{3 R (300)}{M}}$

$⟹$ M = 1kg/mol

Hence, Option "D" is the correct answer.

Suggest Corrections

Similar questions

Q. The number of molecules in

1 kg

of nitrogen gas sample (molar mass = 28 g/mol) is approximately:

Q. Calculate pressure of gas whose molar mass is

29.3 g / m o l .

having density

1.29 k g / m^{3}

at 273 K.

Question 10
The unit of ebuilioscopic constant is
(a) $K k g m o l^{- 1} o r K (m o l a l i t y)^{- 1}$ (b) $m o l k g K^{- 1} o r K^{- 1} (m o l a l i t y)$
(c) $k g m o l^{- 1} o r K^{- 1} (m o l a l i t y)^{- 1}$ (d) $K m o l k g^{- 1} o r (m o l a l i t y)$

Q. Calculate molality of 2.5 g of ethanoic acid

[C H_{3} C O O H]

in 75 g of benzene.

Q. 4.0 kg of a gas occupies 22 . 4 litres at NTP. The specific heat capacity of the gas at constant volume is 5.0

J K^{- 1}

m o l^{- 1}

If the speed of sound in this gas at NTP is 952

m s^{- 1}

then the heat capacity at constant pressure is (Take gas constant R = 8.3

J K^{- 1}

m o l^{- 1}

Join BYJU'S Learning Program

If URMS of a gas is 30R1/2 ms−1 at 27∘C then the molar mass of gas is :

The correct option is D 1 kg/molUrms=√3RTMGiven, Urms=30R1/2⟹30R1/2=√3R(300)M⟹ M = 1kg/molHence, Option "D" is the correct answer.

If $U_{R M S}$ of a gas is 30 $R^{1 / 2}$ ${m s}^{- 1}$ at $27^{\circ} C$ then the molar mass of gas is :

The correct option is D $1$ $k g / m o l$
$U_{r m s} = \sqrt{\frac{3 R T}{M}}$

Given, $U_{r m s} = 30 R^{1 / 2}$

$⟹ 30 R^{1 / 2} = \sqrt{\frac{3 R (300)}{M}}$

$⟹$ M = 1kg/mol

Hence, Option "D" is the correct answer.