If V-100 sin 100t volt- and I-100 sin100t-6A- then find the watt less power in watt-

The correct option is D 2.5 × 10^3√(3) P= V_rms× I_rms×cosϕ = V_0I_0/√(2)×√(2)×cosπ6 = 100 × 100/2×√(3)/2=2.5× 10^3√(3)W ...

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Byju's Answer

Standard XII

Physics

Power Factor

If V=100 si...

Question

If $V = 100 sin 100 t$ volt, and $I = 100 sin (100 t + \frac{π}{6}) A$ . then find the watt less power in watt?

10^{4}

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10^{3}

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10^{2}

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2.5 \times 10^{3} \sqrt{3}

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Solution

The correct option is D $2.5 \times 10^{3} \sqrt{3}$
$P = V_{r m s} \times I_{r m s} \times cos ϕ$

$= \frac{V_{0} I_{0}}{\sqrt{2} \times \sqrt{2}} \times cos \frac{π}{6}$

$= \frac{100 \times 100}{2} \times \frac{\sqrt{3}}{2} = 2.5 \times 10^{3} \sqrt{3} W$

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If V=100sin100t volt, and I=100sin(100t+π6)A. then find the watt less power in watt?

The correct option is D 2.5×103√3P=Vrms×Irms×cosϕ=V0I0√2×√2×cosπ6=100×1002×√32=2.5×103√3W

If $V = 100 sin 100 t$ volt, and $I = 100 sin (100 t + \frac{π}{6}) A$ . then find the watt less power in watt?

The correct option is D $2.5 \times 10^{3} \sqrt{3}$
$P = V_{r m s} \times I_{r m s} \times cos ϕ$

$= \frac{V_{0} I_{0}}{\sqrt{2} \times \sqrt{2}} \times cos \frac{π}{6}$

$= \frac{100 \times 100}{2} \times \frac{\sqrt{3}}{2} = 2.5 \times 10^{3} \sqrt{3} W$