Question

# In an AC circuit $$V$$ and $$I$$ are given by $$V=100\sin{\left(100t\right)}$$volt, $$I=100\sin{\left(100t+\dfrac{\pi}{3}\right)}$$amp the power dissipated in the circuit is

A
5.0 kW
B
2.5 kW
C
1.25 kW
D
zero

Solution

## The correct option is B $$2.5\ kW$$$$P={V}_{rms}\times{I}_{rms}\times\cos{\phi}$$$$=\dfrac{{V}_{\circ}{I}_{\circ}}{2}\cos{\phi}$$$$=\dfrac{100\times 100}{2}\times \dfrac{1}{2}$$$$=2500$$W$$=2.5$$kWPhysics

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