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Question

In an AC circuit $$V$$ and $$I$$ are given by $$V=100\sin{\left(100t\right)}$$volt, $$I=100\sin{\left(100t+\dfrac{\pi}{3}\right)}$$amp the power dissipated in the circuit is


A
5.0 kW
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B
2.5 kW
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C
1.25 kW
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D
zero
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Solution

The correct option is B $$2.5\ kW$$
$$P={V}_{rms}\times{I}_{rms}\times\cos{\phi}$$
$$=\dfrac{{V}_{\circ}{I}_{\circ}}{2}\cos{\phi}$$
$$=\dfrac{100\times 100}{2}\times \dfrac{1}{2}$$
$$=2500$$W
$$=2.5$$kW

Physics

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