In an AC circuit- V and I are given by- V -100 sin 100 t volt- I -100 sin100 t -3 A- Then the power dissipated in the circuit isA- 104 WB- 10 WC- 2500 WD- 5 W

The correct option is C Φ =π/3 V_rms=100/√(2) i_rms=100/√(2) P_avg=V_rmsi_rms COS Φ =100/√(2)×100/√(2)×1/2 = 2500 W ...

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Standard XII

Physics

Alternating Current Applied to an Inductor

In an AC circ...

Question

In an AC circuit, V and I are given by, V=100sin(100t)volt, $I = 100 s i n (100 t + \frac{π}{3}) A$ . Then the power dissipated in the circuit is

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Solution

The correct option is C

$Φ = \frac{π}{3}$

$V_{r m s} = \frac{100}{\sqrt{2}}$

$i_{r m s} = \frac{100}{\sqrt{2}}$
$P_{a v g} = V_{r m s} i_{r m s} C O S Φ$
$= \frac{100}{\sqrt{2}} \times \frac{100}{\sqrt{2}} \times \frac{1}{2}$

= 2500 W

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In an AC circuit, V and I are given by, V=100sin(100t)volt, I=100 sin(100t+π3)A. Then the power dissipated in the circuit is

The correct option is C Φ=π3 Vrms=100√2 irms=100√2 Pavg=Vrmsirms COS Φ =100√2×100√2×12 = 2500 W

In an AC circuit, V and I are given by, V=100sin(100t)volt, $I = 100 s i n (100 t + \frac{π}{3}) A$ . Then the power dissipated in the circuit is

The correct option is C

$Φ = \frac{π}{3}$

$V_{r m s} = \frac{100}{\sqrt{2}}$

$i_{r m s} = \frac{100}{\sqrt{2}}$
$P_{a v g} = V_{r m s} i_{r m s} C O S Φ$
$= \frac{100}{\sqrt{2}} \times \frac{100}{\sqrt{2}} \times \frac{1}{2}$

= 2500 W