If v = (5 - t) m/s and particle starts from origin then its position time graph is

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Solution

The correct option is C
$v = 5 - t \Rightarrow d x = (5 - t) d t$
$x = 5 t - \frac{t^{2}}{2}$

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If v = (5 - t) m/s and particle starts from origin then its position time graph is

The correct option is C v=5−t⇒dx=(5−t)dt x=5t−t22

The correct option is C
$v = 5 - t \Rightarrow d x = (5 - t) d t$
$x = 5 t - \frac{t^{2}}{2}$