If V- gt - V 0 and S- 1-2gt2 - V0t- then t equals-

The correct option is A 2S/V+ V_0 V=gt+ V _∘ #160; Vt=g t ^ 2 +2 V _∘ #160; t S= 1 2 g t ^ 2 + V _∘ #160; t ⟹ 2S=g t ^ 2 +2 V ...

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Standard IX

Mathematics

Applications of Dot Product

If V= gt + V ...

Question

If V= gt + V $_{0}$ and S= $\frac{1}{2} g t^{2}$ + $V_{0} t$ , then t equals:

\frac{2 S}{V + V_{0}}

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\frac{2 S}{V - V_{0}}

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\frac{2 S}{V_{0} - V}

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\frac{2 S}{V}

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2S- V

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Solution

The correct option is A $\frac{2 S}{V + V_{0}}$
$V = g t + V_{\circ} V t = g t^{2} + 2 V_{\circ} t S = \frac{1}{2} g t^{2} + V_{\circ} t ⟹ 2 S = g t^{2} + 2 V_{\circ} t ∴ t = \frac{2 S}{V + V_{\circ}}$

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If V= gt + V0 and S= 12gt2 + V0t, then t equals:

The correct option is A 2SV+V0V=gt+V∘Vt=gt2+2V∘tS=12gt2+V∘t⟹2S=gt2+2V∘t∴t=2SV+V∘

If V= gt + V $_{0}$ and S= $\frac{1}{2} g t^{2}$ + $V_{0} t$ , then t equals:

The correct option is A $\frac{2 S}{V + V_{0}}$
$V = g t + V_{\circ} V t = g t^{2} + 2 V_{\circ} t S = \frac{1}{2} g t^{2} + V_{\circ} t ⟹ 2 S = g t^{2} + 2 V_{\circ} t ∴ t = \frac{2 S}{V + V_{\circ}}$