If $v = x^{2} - 5 x + 4$ ,find acceleration of the particle when velocity of the particle is zero

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Solution

The correct option is C 0
Given , $v = x^{2} - 5 x + 4 ⟹ \frac{d v}{d x} = 2 x - 5$

So,when velocity $(v)$ is $0$ , so as the acceleration (= $v \times$ $\frac{d v}{d x}$ ).

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If v=x2−5x+4,find acceleration of the particle when velocity of the particle is zero

The correct option is C 0Given ,v=x2−5x+4⟹dvdx=2x−5So,when velocity(v) is 0, so as the acceleration (=v× dvdx).

If $v = x^{2} - 5 x + 4$ ,find acceleration of the particle when velocity of the particle is zero

The correct option is C 0
Given , $v = x^{2} - 5 x + 4 ⟹ \frac{d v}{d x} = 2 x - 5$

So,when velocity $(v)$ is $0$ , so as the acceleration (= $v \times$ $\frac{d v}{d x}$ ).