If $v = x^{2} - 5 x + 4,$ , Find the acceleration of the particle when velocity of the particle is zero.

0

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3

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none of these

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Solution

The correct option is A $0$
$v = x^{2} - 5 x + 4$
$a = \frac{d v}{d t} = 2 x \frac{d x}{d t} - 5 \frac{d x}{d t} = 2 x v - 5 v$
since $v = 0$
$a = 0$

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Q. If

v = x^{2} - 5 x + 4

,find acceleration of the particle when velocity of the particle is zero

The velocity of a moving particle along the x-axis is given as $v = x^{2} - 5 x + 4 (i n m/s),$ where x denotes the $x - c o o r d i n a t e$ of the particle in meters. Find the magnitude of the acceleration of the particle when the velocity of the particle is zero?