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Question

If a=2^i+5^j+8^k,b=^i+3^j+7^k and c=3^i+2^j+^k then find the value of a×(b×c).

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Solution

Find the value of a×(b×c)
b×c=∣ ∣ ∣^i^j^k137321∣ ∣ ∣
b×c=^i(314)^j(121)+^k(29)
(b×c)=11^i+20^j7^k
a×(b×c)=∣ ∣ ∣^i^j^k25811207∣ ∣ ∣
a×(b×c)=^i(35160)^j(14+88)+^k(40+55)
a×(b×c)=195^i74^j+95^k.

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