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Question

If a=2^i+^j+3^k,b=^i+2^j+^k and c=3^i+^j+2^k. Find a(b×c).

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Solution

b×c=∣ ∣ijk121332∣ ∣
=^i(41)^j(23)+^k(16)=3^i+5^j7^k
a(b×c)=(2^i+^j+3^k)(3^i+5^j7^k)=6+521=1121=10

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