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Byju's Answer
Standard XII
Physics
Vector Component
If a⃗=3î-6î...
Question
If
→
a
=
3
^
i
−
6
^
i
−
^
k
,
→
b
=
−
1
^
i
+
4
^
i
−
3
^
k
,
→
c
=
3
^
i
−
4
^
i
−
12
^
k
, then the length of projection of
→
a
×
→
b
on
¯
¯
c
is
A
250
13
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B
5
√
2
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C
250
√
13
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D
14
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Solution
The correct option is
C
14
(
¯
¯
¯
a
×
¯
¯
b
)
=
22
i
+
8
+
18
k
Hence,
(
¯
¯
¯
a
×
¯
¯
b
)
.
(
¯
¯
c
)
=
(
22
i
+
8
+
18
k
)
(
3
i
−
4
j
−
12
k
)
=
22
−
32
−
216
=
−
182
Hence the value of the given expression will be
|
−
182
√
3
2
+
4
2
+
12
2
|
=
182
13
=
14
Suggest Corrections
0
Similar questions
Q.
If
→
a
=
3
^
i
−
2
^
j
+
^
k
,
→
b
=
2
^
i
−
4
^
j
−
3
^
k
,
→
c
=
−
1
^
i
+
2
^
j
+
2
^
k
then
→
a
+
→
b
+
→
c
=
Q.
I: If
→
a
=
3
^
i
−
2
^
j
+
^
k
,
→
b
=
2
^
i
−
4
^
j
−
3
^
k
,
→
c
=
−
^
i
+
2
^
j
+
2
^
k
then
→
a
+
→
b
+
→
c
=
4
^
i
−
4
^
j
II: If
→
a
=
^
i
−
^
j
+
2
^
k
,
→
b
=
2
^
i
+
3
^
j
+
^
k
,
→
c
=
^
i
−
^
k
, then magnitude of
→
a
+
2
→
b
−
3
→
c
is
√
78
Q.
Let
→
a
=
^
i
+
^
j
+
^
k
,
→
b
=
^
i
−
^
j
+
^
k
and
→
c
=
^
i
−
^
j
−
^
k
be three vectors. A vector
→
v
in the plane of
→
a
and
→
b
, whose projection on
→
c
is
2
√
3
, is given by
Q.
If
→
a
=
2
^
i
+
3
^
j
−
4
^
k
,
→
b
=
^
i
+
^
j
+
^
k
and
→
c
=
4
^
i
+
3
^
k
, then
|
→
a
×
(
→
b
×
→
c
)
|
=
Q.
Let
→
a
=
^
i
+
^
j
+
^
k
,
→
b
=
−
3
^
i
+
^
k
and
→
c
=
^
i
+
2
^
j
+
3
^
k
, then the ascending order of magnitudes of
A
)
[
→
a
×
→
b
→
b
×
→
c
→
c
×
→
a
]
B
)
[
→
a
+
→
b
→
b
+
→
c
→
c
+
→
a
]
C
)
[
→
a
→
b
→
c
]
[
→
a
→
b
→
c
]
−
1
D
)
[
→
a
−
→
b
→
b
−
→
c
→
c
−
→
a
]
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